Just checking how good at math you people are.

[Jojan]

The function is h(x) = (f(x))² + (g(x))²
* f(0) = 2 and g(0)=1
* f'(x) = g(x) and g'(x) = -f(x)
What is h'(x)?
Use h'(x) to show that h(x) = 5 for every value of x.

Do not give me the answer, I allready know it. I just like to know how great at math you people are.

[Amiralanal]

i ate bloodpudding for dinner. the lingonberryjam wasnt very good.

[Bazza]

easy!!
degree level maths module, yeah baby!!

[sKratch]

First order diff eq with initial conditions. Piece of cake.

[Endymion]

why use h' when it's so easy to prove that sin^2+cos^2 = 1?